Optimal. Leaf size=171 \[ -\frac {d \left (20 a c d+6 b c^2+9 b d^2\right ) \sin (e+f x) \cos (e+f x)}{24 f}-\frac {\left (4 a d \left (4 c^2+d^2\right )+3 b \left (c^3+4 c d^2\right )\right ) \cos (e+f x)}{6 f}+\frac {1}{8} x \left (8 a c^3+12 a c d^2+12 b c^2 d+3 b d^3\right )-\frac {(4 a d+3 b c) \cos (e+f x) (c+d \sin (e+f x))^2}{12 f}-\frac {b \cos (e+f x) (c+d \sin (e+f x))^3}{4 f} \]
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Rubi [A] time = 0.21, antiderivative size = 171, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.087, Rules used = {2753, 2734} \[ -\frac {\left (4 a d \left (4 c^2+d^2\right )+3 b \left (c^3+4 c d^2\right )\right ) \cos (e+f x)}{6 f}-\frac {d \left (20 a c d+6 b c^2+9 b d^2\right ) \sin (e+f x) \cos (e+f x)}{24 f}+\frac {1}{8} x \left (8 a c^3+12 a c d^2+12 b c^2 d+3 b d^3\right )-\frac {(4 a d+3 b c) \cos (e+f x) (c+d \sin (e+f x))^2}{12 f}-\frac {b \cos (e+f x) (c+d \sin (e+f x))^3}{4 f} \]
Antiderivative was successfully verified.
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Rule 2734
Rule 2753
Rubi steps
\begin {align*} \int (a+b \sin (e+f x)) (c+d \sin (e+f x))^3 \, dx &=-\frac {b \cos (e+f x) (c+d \sin (e+f x))^3}{4 f}+\frac {1}{4} \int (c+d \sin (e+f x))^2 (4 a c+3 b d+(3 b c+4 a d) \sin (e+f x)) \, dx\\ &=-\frac {(3 b c+4 a d) \cos (e+f x) (c+d \sin (e+f x))^2}{12 f}-\frac {b \cos (e+f x) (c+d \sin (e+f x))^3}{4 f}+\frac {1}{12} \int (c+d \sin (e+f x)) \left (12 a c^2+15 b c d+8 a d^2+\left (6 b c^2+20 a c d+9 b d^2\right ) \sin (e+f x)\right ) \, dx\\ &=\frac {1}{8} \left (8 a c^3+12 b c^2 d+12 a c d^2+3 b d^3\right ) x-\frac {\left (4 a d \left (4 c^2+d^2\right )+3 b \left (c^3+4 c d^2\right )\right ) \cos (e+f x)}{6 f}-\frac {d \left (6 b c^2+20 a c d+9 b d^2\right ) \cos (e+f x) \sin (e+f x)}{24 f}-\frac {(3 b c+4 a d) \cos (e+f x) (c+d \sin (e+f x))^2}{12 f}-\frac {b \cos (e+f x) (c+d \sin (e+f x))^3}{4 f}\\ \end {align*}
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Mathematica [A] time = 0.68, size = 143, normalized size = 0.84 \[ \frac {-24 \left (3 a d \left (4 c^2+d^2\right )+b \left (4 c^3+9 c d^2\right )\right ) \cos (e+f x)+3 \left (-8 d \left (3 a c d+b \left (3 c^2+d^2\right )\right ) \sin (2 (e+f x))+4 (e+f x) \left (8 a c^3+12 a c d^2+12 b c^2 d+3 b d^3\right )+b d^3 \sin (4 (e+f x))\right )+8 d^2 (a d+3 b c) \cos (3 (e+f x))}{96 f} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.48, size = 145, normalized size = 0.85 \[ \frac {8 \, {\left (3 \, b c d^{2} + a d^{3}\right )} \cos \left (f x + e\right )^{3} + 3 \, {\left (8 \, a c^{3} + 12 \, b c^{2} d + 12 \, a c d^{2} + 3 \, b d^{3}\right )} f x - 24 \, {\left (b c^{3} + 3 \, a c^{2} d + 3 \, b c d^{2} + a d^{3}\right )} \cos \left (f x + e\right ) + 3 \, {\left (2 \, b d^{3} \cos \left (f x + e\right )^{3} - {\left (12 \, b c^{2} d + 12 \, a c d^{2} + 5 \, b d^{3}\right )} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{24 \, f} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.19, size = 152, normalized size = 0.89 \[ \frac {b d^{3} \sin \left (4 \, f x + 4 \, e\right )}{32 \, f} + \frac {1}{8} \, {\left (8 \, a c^{3} + 12 \, b c^{2} d + 12 \, a c d^{2} + 3 \, b d^{3}\right )} x + \frac {{\left (3 \, b c d^{2} + a d^{3}\right )} \cos \left (3 \, f x + 3 \, e\right )}{12 \, f} - \frac {{\left (4 \, b c^{3} + 12 \, a c^{2} d + 9 \, b c d^{2} + 3 \, a d^{3}\right )} \cos \left (f x + e\right )}{4 \, f} - \frac {{\left (3 \, b c^{2} d + 3 \, a c d^{2} + b d^{3}\right )} \sin \left (2 \, f x + 2 \, e\right )}{4 \, f} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.26, size = 182, normalized size = 1.06 \[ \frac {a \,c^{3} \left (f x +e \right )-3 a \,c^{2} d \cos \left (f x +e \right )+3 a c \,d^{2} \left (-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )-\frac {a \,d^{3} \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )}{3}-b \,c^{3} \cos \left (f x +e \right )+3 b \,c^{2} d \left (-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )-c \,d^{2} b \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )+b \,d^{3} \left (-\frac {\left (\sin ^{3}\left (f x +e \right )+\frac {3 \sin \left (f x +e \right )}{2}\right ) \cos \left (f x +e \right )}{4}+\frac {3 f x}{8}+\frac {3 e}{8}\right )}{f} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.17, size = 175, normalized size = 1.02 \[ \frac {96 \, {\left (f x + e\right )} a c^{3} + 72 \, {\left (2 \, f x + 2 \, e - \sin \left (2 \, f x + 2 \, e\right )\right )} b c^{2} d + 72 \, {\left (2 \, f x + 2 \, e - \sin \left (2 \, f x + 2 \, e\right )\right )} a c d^{2} + 96 \, {\left (\cos \left (f x + e\right )^{3} - 3 \, \cos \left (f x + e\right )\right )} b c d^{2} + 32 \, {\left (\cos \left (f x + e\right )^{3} - 3 \, \cos \left (f x + e\right )\right )} a d^{3} + 3 \, {\left (12 \, f x + 12 \, e + \sin \left (4 \, f x + 4 \, e\right ) - 8 \, \sin \left (2 \, f x + 2 \, e\right )\right )} b d^{3} - 96 \, b c^{3} \cos \left (f x + e\right ) - 288 \, a c^{2} d \cos \left (f x + e\right )}{96 \, f} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 8.08, size = 183, normalized size = 1.07 \[ \frac {2\,a\,d^3\,\cos \left (3\,e+3\,f\,x\right )-6\,b\,d^3\,\sin \left (2\,e+2\,f\,x\right )+\frac {3\,b\,d^3\,\sin \left (4\,e+4\,f\,x\right )}{4}-18\,a\,d^3\,\cos \left (e+f\,x\right )-24\,b\,c^3\,\cos \left (e+f\,x\right )-72\,a\,c^2\,d\,\cos \left (e+f\,x\right )-54\,b\,c\,d^2\,\cos \left (e+f\,x\right )+24\,a\,c^3\,f\,x+9\,b\,d^3\,f\,x+6\,b\,c\,d^2\,\cos \left (3\,e+3\,f\,x\right )-18\,a\,c\,d^2\,\sin \left (2\,e+2\,f\,x\right )-18\,b\,c^2\,d\,\sin \left (2\,e+2\,f\,x\right )+36\,a\,c\,d^2\,f\,x+36\,b\,c^2\,d\,f\,x}{24\,f} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 1.86, size = 386, normalized size = 2.26 \[ \begin {cases} a c^{3} x - \frac {3 a c^{2} d \cos {\left (e + f x \right )}}{f} + \frac {3 a c d^{2} x \sin ^{2}{\left (e + f x \right )}}{2} + \frac {3 a c d^{2} x \cos ^{2}{\left (e + f x \right )}}{2} - \frac {3 a c d^{2} \sin {\left (e + f x \right )} \cos {\left (e + f x \right )}}{2 f} - \frac {a d^{3} \sin ^{2}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {2 a d^{3} \cos ^{3}{\left (e + f x \right )}}{3 f} - \frac {b c^{3} \cos {\left (e + f x \right )}}{f} + \frac {3 b c^{2} d x \sin ^{2}{\left (e + f x \right )}}{2} + \frac {3 b c^{2} d x \cos ^{2}{\left (e + f x \right )}}{2} - \frac {3 b c^{2} d \sin {\left (e + f x \right )} \cos {\left (e + f x \right )}}{2 f} - \frac {3 b c d^{2} \sin ^{2}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {2 b c d^{2} \cos ^{3}{\left (e + f x \right )}}{f} + \frac {3 b d^{3} x \sin ^{4}{\left (e + f x \right )}}{8} + \frac {3 b d^{3} x \sin ^{2}{\left (e + f x \right )} \cos ^{2}{\left (e + f x \right )}}{4} + \frac {3 b d^{3} x \cos ^{4}{\left (e + f x \right )}}{8} - \frac {5 b d^{3} \sin ^{3}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{8 f} - \frac {3 b d^{3} \sin {\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{8 f} & \text {for}\: f \neq 0 \\x \left (a + b \sin {\relax (e )}\right ) \left (c + d \sin {\relax (e )}\right )^{3} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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